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JEE PYQ: Chemical Equilibrium Question 20

Question 20 - 2020 (09 Jan Shift 1)

In the figure shown below reactant A (represented by square) is in equilibrium with product B (represented by circle). The equilibrium constant is:

Equilibrium mixture showing 3 squares (reactant A) and 6 circles (product B)

(1) 4 (2) 8 (3) 1 (4) 2

Show Answer

Answer: (4) 2

Solution

$K = \frac{[B]}{[A]} = \frac{6}{3} = 2$.


Learning Progress: Step 20 of 30 in this series