JEE PYQ: Chemical Equilibrium Question 20
Question 20 - 2020 (09 Jan Shift 1)
In the figure shown below reactant A (represented by square) is in equilibrium with product B (represented by circle). The equilibrium constant is:
(1) 4 (2) 8 (3) 1 (4) 2
Show Answer
Answer: (4) 2
Solution
$K = \frac{[B]}{[A]} = \frac{6}{3} = 2$.