JEE PYQ: Chemical Equilibrium Question 26
Question 26 - 2019 (11 Jan Shift 1)
Consider the reaction $\text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g)$
The equilibrium constant is $K_p$. If pure ammonia is left to dissociate, the partial pressure of ammonia at equilibrium is given by (Assume $p_{\text{NH}3} \ll p{\text{total}}$):
(1) $\frac{3^{3/2} K_p^{1/2} P^2}{16}$ (2) $\frac{K_p^{1/2} P^2}{16}$ (3) $\frac{K_p^{1/2} P^2}{4}$ (4) $\frac{3^{3/2} K_p^{1/2} P^2}{4}$
Show Answer
Answer: (1) $\frac{3^{3/2} K_p^{1/2} P^2}{16}$
Solution
Since $p_{\text{NH}3} \ll P$, $P{\text{N}2} = P/4$, $P{\text{H}2} = 3P/4$. Solving gives $P{\text{NH}_3} = \frac{3^{3/2} K_p^{1/2} P^2}{16}$.
BETA
