JEE PYQ: Chemical Equilibrium Question 5
Question 5 - 2021 (18 Mar Shift 2)
The gas phase reaction $2\text{A}(g) \rightleftharpoons \text{A}_2(g)$ at 400 K has $\Delta G^\circ = +25.2 \text{ kJ mol}^{-1}$.
The equilibrium constant $K_C$ for this reaction is ____ $\times 10^{-2}$. (Round off to the Nearest Integer)
[Use: $R = 8.3 \text{ J mol}^{-1} \text{K}^{-1}$, $\ln 10 = 2.3$, $\log_{10} 2 = 0.30$, 1 atm = 1 bar, antilog $(-0.3) = 0.501$]
Show Answer
Answer: 166
Solution
$\Delta_r G^0 = -RT \ln K_p$; solving gives $K_C = 166 \times 10^{-2}$.
BETA
