JEE PYQ: Chemical Kinetics Question 14
Question 14 - 2020 (03 Sep Shift 2)
For the reaction $2\text{A} + 3\text{B} + \frac{3}{2}\text{C} \to 3\text{P}$, which statement is correct?
(1) $\dfrac{d n_A}{dt} = \dfrac{3}{2}\dfrac{d n_B}{dt} = \dfrac{3}{4}\dfrac{d n_C}{dt}$
(2) $\dfrac{d n_A}{dt} = \dfrac{d n_B}{dt} = \dfrac{d n_C}{dt}$
(3) $\dfrac{d n_A}{dt} = \dfrac{2}{3}\dfrac{d n_B}{dt} = \dfrac{4}{3}\dfrac{d n_C}{dt}$
(4) $\dfrac{d n_A}{dt} = \dfrac{2}{3}\dfrac{d n_B}{dt} = \dfrac{3}{4}\dfrac{d n_C}{dt}$
Show Answer
Answer: (3)
Solution
For a given reaction, rate $= \frac{1}{2}\frac{dn_A}{dt} = \frac{1}{3}\frac{dn_B}{dt} = \frac{2}{3}\frac{dn_C}{dt}$. So $\frac{dn_A}{dt} = \frac{2}{3}\frac{dn_B}{dt} = \frac{4}{3}\frac{dn_C}{dt}$.
BETA
