JEE PYQ: Chemical Kinetics Question 23
Question 23 - 2020 (07 Jan Shift 2)
For the reaction $2\text{H}_2(\text{g}) + 2\text{NO}(\text{g}) \to \text{N}_2(\text{g}) + 2\text{H}_2\text{O}(\text{g})$ the observed rate expression is, rate $= k_f[\text{NO}]^2[\text{H}_2]$. The rate expression for the reverse reaction is:
(1) $k_b[\text{N}_2][\text{H}_2\text{O}]^2$
(2) $k_b[\text{N}_2][\text{H}_2\text{O}]^2/[\text{NO}]$
(3) $k_b[\text{N}_2][\text{H}_2\text{O}]$
(4) $k_b[\text{N}_2][\text{H}_2\text{O}]^2/[\text{H}_2]$
Show Answer
Answer: (4)
Solution
Rate of forward reaction $= k_f[\text{NO}]^2[\text{H}_2]$. Observed rate $= k_f[\text{NO}]^2[\text{H}_2]$. $\frac{\text{Observed rate}}{[\text{H}_2]} = \frac{\text{Rate of forward reaction}}{[\text{H}_2]}$. Rate of backward reaction $= \frac{k_b[\text{N}_2][\text{H}_2\text{O}]^2}{[\text{H}_2]}$.
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