JEE PYQ: Chemical Kinetics Question 29
Question 29 - 2019 (08 Apr Shift 2)
For a reaction scheme $\text{A} \xrightarrow{k_1} \text{B} \xrightarrow{k_2} \text{C}$, if the rate of formation of B is set to be zero then the concentration of B is given by:
(1) $(k_1 - k_2)[\text{A}]$
(2) $k_1 k_2[\text{A}]$
(3) $(k_1 + k_2)[\text{A}]$
(4) $\left(\dfrac{k_1}{k_2}\right)[\text{A}]$
Show Answer
Answer: (4)
Solution
$\frac{d[\text{B}]}{dt} = k_1[\text{A}] - k_2[\text{B}] = 0$. $[\text{B}] = \frac{k_1[\text{A}]}{k_2}$.
BETA
