JEE PYQ: Chemical Kinetics Question 5
Question 5 - 2021 (18 Mar Shift 1)
$2\text{NO(g)} + \text{Cl}_2(\text{g}) \rightleftharpoons 2\text{NOCl(s)}$
This reaction was studied at $-10°\text{C}$ and the following data was obtained:
| run | $[\text{NO}]_0$ | $[\text{Cl}_2]_0$ | $r_0$ |
|---|---|---|---|
| 1 | 0.10 | 0.10 | 0.18 |
| 2 | 0.10 | 0.20 | 0.35 |
| 3 | 0.20 | 0.20 | 1.40 |
$[\text{NO}]_0$ and $[\text{Cl}_2]_0$ are the initial concentrations and $r_0$ is the initial reaction rate. The overall order of the reaction is ____. (Round off to the Nearest Integer).
Show Answer
Answer: 3
Solution
$r = k[\text{NO}]^m[\text{Cl}_2]^n$. From runs 1 and 2: $\frac{0.18}{0.35} = \left(\frac{0.10}{0.20}\right)^n$, so $n = 1$. From runs 1 and 3: $m = 2$. Overall order $= m + n = 3$.