JEE PYQ: Electrochemistry Question 21
Question 21 - 2020 (07 Jan Shift 1)
Given that the standard potentials ($E^0$) of $\text{Cu}^{2+}/\text{Cu}$ and $\text{Cu}^+/\text{Cu}$ are 0.34 V and 0.522 V respectively, the $E^0$ of $\text{Cu}^{2+}/\text{Cu}^+$ is:
(1) +0.182 V
(2) +0.158 V
(3) -0.182 V
(4) -0.158 V
Show Answer
Answer: (2) +0.158 V
Solution
Using Gibbs energy: $E^0 = 2(0.34) - 0.522 = 0.158$ V.