JEE PYQ: Electrochemistry Question 22
Question 22 - 2020 (07 Jan Shift 2)
The equation that is incorrect is:
(1) $(\Lambda^0_m){\text{NaBr}} - (\Lambda^0_m){\text{NaCl}} = (\Lambda^0_m){\text{KBr}} - (\Lambda^0_m){\text{KCl}}$
(2) $(\Lambda^0_m){\text{KCl}} - (\Lambda^0_m){\text{NaCl}} = (\Lambda^0_m){\text{KBr}} - (\Lambda^0_m){\text{NaBr}}$
(3) $(\Lambda^0_m){\text{H}2\text{O}} = (\Lambda^0_m){\text{HCl}} + (\Lambda^0_m){\text{NaOH}} - (\Lambda^0_m)_{\text{NaCl}}$
(4) $(\Lambda^0_m){\text{NaBr}} - (\Lambda^0_m){\text{NaI}} = (\Lambda^0_m){\text{KBr}} - (\Lambda^0_m){\text{NaBr}}$
Show Answer
Answer: (4) $(\Lambda^0_m){\text{NaBr}} - (\Lambda^0_m){\text{NaI}} = (\Lambda^0_m){\text{KBr}} - (\Lambda^0_m){\text{NaBr}}$
Solution
LHS = $\Lambda^0_{\text{Br}^-} - \Lambda^0_{\text{I}^-}$, RHS = $\Lambda^0_{\text{K}^+} - \Lambda^0_{\text{Na}^+}$. LHS $\neq$ RHS.
BETA
