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What would be the electrode potential for the given half cell reaction at pH = 5? $2\text{H}_2\text{O} \rightarrow \text{O}2 + 4\text{H}^\oplus + 4e^-$; $E^0{\text{red}} = 1.23$ V
(R = 8.314 J mol$^{-1}$ K$^{-1}$; Temp = 298 K; oxygen under std. atm. pressure of 1 bar)
$E = 1.23 + 0.0591 \times 5 = 1.52$ V.
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