JEE PYQ: Electrochemistry Question 24
Question 24 - 2020 (08 Jan Shift 2)
For an electrochemical cell $\text{Sn}(s)|\text{Sn}^{2+}(aq, 1\text{M})||\text{Pb}^{2+}(aq, 1\text{M})|\text{Pb}(s)$ the ratio $\frac{[\text{Sn}^{2+}]}{[\text{Pb}^{2+}]}$ when this cell attains equilibrium is ____.
(Given: $E^0_{\text{Sn}^{2+}|\text{Sn}} = -0.14$ V, $E_{\text{Pb}|\text{Pb}} = -0.13$ V, $\frac{2.303RT}{F} = 0.06$)
Show Answer
Answer: 2.15
Solution
At equilibrium $E_{\text{cell}} = 0$. $\frac{[\text{Sn}^{2+}]}{[\text{Pb}^{2+}]} = 10^{1/3} = 2.15$.
BETA
