JEE PYQ: Electrochemistry Question 27
Question 27 - 2019 (08 Apr Shift 1)
Given that $E^0_{\text{O}_2/\text{H}2\text{O}} = +1.23$ V; $E^0{\text{S}_2\text{O}_8^{2-}/\text{SO}4^{2-}} = 2.05$ V; $E^0{\text{Br}2/\text{Br}^-} = +1.09$ V; $E^0{\text{Au}^{3+}/\text{Au}} = +1.4$ V. The strongest oxidising agent is:
(1) Au$^{3+}$
(2) O$_2$
(3) S$_2$O$_8^{2-}$
(4) Br$_2$
Show Answer
Answer: (3) S$_2$O$_8^{2-}$
Solution
Highest reduction potential = strongest oxidising agent. $\text{S}_2\text{O}_8^{2-}$ has $E^0 = 2.05$ V (highest).
BETA
