JEE PYQ: Electrochemistry Question 6
Question 6 - 2021 (24 Feb Shift 2)
The magnitude of the change in oxidising power of the $\text{MnO}_4^-/\text{Mn}^{2+}$ couple is $x \times 10^{-4}$ V, if the H$^+$ concentration is decreased from 1M to $10^{-4}$M at 25$^\circ$C. (Assume concentration of $\text{MnO}_4^-$ and $\text{Mn}^{2+}$ to be same on change in H$^+$ concentration). The value of x is ____.
(Rounded off to the nearest integer) [Given: $\frac{2.303RT}{F} = 0.059$]
Show Answer
Answer: 3776
Solution
$|E_2 - E_1| = \frac{0.059}{5} \times 32 = 3776 \times 10^{-4}$. So $x = 3776$.
BETA
