JEE PYQ: General Organic Chemistry Question 13
Question 13 - 2021 (26 Feb Shift 2)
In $\overset{1}{\text{CH}_2} = \overset{2}{\text{C}} = \overset{3}{\text{CH}} - \overset{4}{\text{CH}_3}$ molecule, the hybridization of carbon 1, 2, 3 and 4 respectively are:
(1) $sp^2$, $sp$, $sp^2$, $sp^3$
(2) $sp^2$, $sp^2$, $sp^2$, $sp^2$
(3) $sp^2$, $sp^2$, $sp^2$, $sp^3$
(4) $sp^2$, $sp$, $sp^3$, $sp^3$
Show Answer
Answer: (1)
Solution
$\text{CH}2 = \text{C} = \text{CH}{sp^2} - \text{CH}_{sp^3}$. Carbon 1 is $sp^2$, Carbon 2 is $sp$ (two double bonds), Carbon 3 is $sp^2$, Carbon 4 is $sp^3$.
BETA
