JEE PYQ: Hydrogen Question 10
Question 10 - 2020 (03 Sep Shift 1)
The volume strength of 8.9 M $\text{H}_2\text{O}_2$ solution calculated at 273 K and 1 atm is ______. ($R = 0.0821$ L atm $\text{K}^{-1}$ $\text{mol}^{-1}$) (rounded off to the nearest integer)
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Answer: 100
Solution
Molarity of $\text{H}_2\text{O}_2$ solution $= \frac{\text{Volume strength}}{11.2}$. Volume strength $= 8.9 \times 11.2 = 99.68 \approx 100$ V.