JEE PYQ: Ionic Equilibrium Question 1
Question 1 - 2021 (16 Mar Shift 1)
Type: Numerical
Two salts $A_2X$ and $MX$ have the same value of solubility product of $4.0 \times 10^{-12}$. The ratio of their molar solubilities i.e. $\frac{S(A_2X)}{S(MX)} =$ ____. (Round off to the Nearest Integer).
Show Answer
Answer: 50
Solution
For $A_2X$: $A_2X \rightarrow 2A^+ + X^{2-}$
$K_{sp} = 4S_1^3 = 4 \times 10^{-12}$, so $S_1 = 10^{-4}$
For $MX$: $MX \rightarrow M^+ + X^-$
$K_{sp} = S_2^2 = 4 \times 10^{-12}$, so $S_2 = 2 \times 10^{-6}$
$\frac{S_{A_2X}}{S_{MX}} = \frac{10^{-4}}{2 \times 10^{-6}} = 50$
BETA
