JEE PYQ: Ionic Equilibrium Question 4
Question 4 - 2021 (18 Mar Shift 1)
Type: Numerical
In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is ____ M. (Round off to the Nearest Integer).
[Given: $\text{pKa (acetic acid)} = 4.74$]
Show Answer
Answer: 10
Solution
$\text{pH} = \text{pKa} + \log \frac{[\text{CB}]}{[\text{WA}]}$
$5.74 = 4.74 + \log \frac{[\text{CB}]}{1}$
$\log [\text{CB}] = 1$
$[\text{CB}] = 10$ M
BETA
