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JEE PYQ: P Block Elements Question 12

Question 12 - 2021 (24 Feb Shift 1)

Given below are two statements:

Statement I: Colourless cupric metaborate is reduced to cuprous metaborate in a luminous flame.

Statement II: Cuprous metaborate is obtained by heating boric anhydride and copper sulphate in a non-luminous flame. In the light of the above statements, choose the most appropriate answer from the options given below.

(1) Statement I is false but statement II is true.

(2) Statement I is true but Statement II is false.

(3) Both Statement I and Statement II are true.

(4) Both Statement I and Statement II are false.

Show Answer

Answer: (4)

Solution

Both are False. (1) Copper sulphate forms copper meta borate with boric anhydride: $\text{CuSO}_4 \to \text{CuO} + \text{SO}_3$. $\text{CuO} + \text{B}_2\text{O}_3 \to \text{Cu(BO}_2\text{)}_2$ (blue in cold oxidising flame, non-luminous flame). (2) Blue coloured metal borate is reduced to copper in a luminous flame.


Learning Progress: Step 12 of 77 in this series