JEE PYQ: P Block Elements Question 18
Question 18 - 2021 (26 Feb Shift 1)
Find A, B and C in the following reaction: $\text{NH}_3 + \text{A} + \text{CO}_2 \to (\text{NH}_4)_2\text{CO}_3$ $(\text{NH}_4)_2\text{CO}_3 + \text{H}_2\text{O} + \text{B} = \text{NH}_4\text{HCO}_3$ $\text{NH}_4\text{HCO}_3 + \text{NaCl} \to \text{NaHCO}_3 + \text{C}$
(1) A $= \text{H}_2\text{O}$; B $= \text{CO}_2$; C $= \text{NaHCO}_3$
(2) A $= \text{H}_2\text{O}$; B $= \text{O}_2$; C $= \text{Na}_2\text{CO}_3$
(3) A $= \text{O}_2$; B $= \text{CO}_2$; C $= \text{Na}_2\text{CO}_3$
(4) A $= \text{H}_2\text{O}$; B $= \text{O}_2$; C $= \text{NaHCO}_3$
(1) $\text{NH}_3 + \text{H}_2\text{O} + \text{CO}_2 \to (\text{NH}_4)_2\text{CO}_3$
(2) $(\text{NH}_4)_2\text{CO}_3 + \text{H}_2\text{O} + \text{CO}_2 \to \text{NH}_4\text{HCO}_3$
(3) $\text{NH}_4\text{HCO}_3 + \text{NaCl} \to \text{NaHCO}_3 + \text{NH}_4\text{Cl}$
Show Answer
Answer: (1)
Solution
This is Solvay process: (1) $\text{NH}_3 + \text{H}_2\text{O} + \text{CO}_2 \to (\text{NH}_4)_2\text{CO}_3$. (2) $(\text{NH}_4)_2\text{CO}_3 + \text{H}_2\text{O} + \text{CO}_2 \to \text{NH}_4\text{HCO}_3$. (3) $\text{NH}_4\text{HCO}_3 + \text{NaCl} \to \text{NH}_4\text{Cl} + \text{NaHCO}_3$.
BETA
