JEE PYQ: P Block Elements Question 21
Question 21 - 2021 (26 Feb Shift 2)
Match List-I with List-II:
| List-I | List-II | ||
|---|---|---|---|
| (a) | Sodium Carbonate | (i) | Deacon |
| (b) | Titanium | (ii) | Caster-Kellner |
| (c) | Chlorine | (iii) | Van-Arkel |
| (d) | Sodium hydroxide | (iv) | Solvay |
Choose the correct answer from the option given below:
(1) (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
(2) (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
(3) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
(4) (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
Show Answer
Answer: (2)
Solution
Sodium carbonate: Solvay. Titanium: Van Arkel method. Chlorine: Deacon’s process ($\text{HCl} + \text{O}_2 \xrightarrow{\text{CuCl}_2} \text{H}_2\text{O} + \text{Cl}_2$). Sodium hydroxide: Caster-Kellner cell.