JEE PYQ: P Block Elements Question 28
Question 28 - 2020 (04 Sep Shift 2)
The reaction in which the hybridisation of the underlined atom is affected is:
(1) $\underline{\text{H}_3}\text{PO}_2 \xrightarrow{\text{Disproportionation}}$
(2) $\text{H}_2\text{SO}_4 + \text{NaCl} \xrightarrow{420\text{ K}}$
(3) $\underline{\text{NH}_3} \xrightarrow{\text{H}^+}$
(4) $\underline{\text{Xe}}\text{F}_4 + \text{SbF}_5 \to$
Show Answer
Answer: (4)
Solution
(a) $\text{H}_3\text{PO}_2$: $sp^3 \to sp^3$ (Disproportionation). (b) $\text{H}_2\text{SO}_4 + \text{NaCl}$: $sp^3 \to sp^3$. (c) $\text{NH}_3 \xrightarrow{\text{H}^+} \text{NH}_4^+$: $sp^3 \to sp^3$. (d) $\text{XeF}_4 + \text{SbF}_5 \to [\text{XeF}_3]^+[\text{SbF}_6]^-$: $sp^3d^2 \to sp^3d$.
BETA
