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The reaction of NO with $\text{N}_2\text{O}_4$ at 250 K gives:
(1) $\text{N}_2\text{O}$
(2) $\text{NO}_2$
(3) $\text{N}_2\text{O}_3$
(4) $\text{N}_2\text{O}_5$
$2\text{NO} + \text{N}_2\text{O}_4 \xrightarrow{250\text{ K}} 2\text{N}_2\text{O}_3$.
BETA
