JEE PYQ: P Block Elements Question 38
Question 38 - 2020 (08 Jan Shift 1)
When gypsum is heated to 393 K, it forms:
(1) Anhydrous $\text{CaSO}_4$
(2) $\text{CaSO}_4 \cdot 5\text{H}_2\text{O}$
(3) $\text{CaSO}_4 \cdot 0.5\text{H}_2\text{O}$
(4) Dead burnt plaster
Show Answer
Answer: (3)
Solution
Gypsum on heating to 393 K forms plaster of Paris. $\text{CaSO}_4 \cdot 2\text{H}_2\text{O} \xrightarrow{393\text{K}} \text{CaSO}_4 \cdot 0.5\text{H}_2\text{O} + 1.5\text{H}_2\text{O}$.
BETA
