JEE PYQ: P Block Elements Question 44
Question 44 - 2020 (09 Jan Shift 2)
The reaction of $\text{H}_3\text{N}_3\text{B}_3\text{Cl}_3$(A) with $\text{LiBH}_4$ in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to $\text{H}_3\text{N}_3\text{B}_3(\text{Me})_3$. Compounds (B) and (C) respectively, are:
(1) Borazine and MeBr
(2) Diborane and MeMgBr
(3) Boron nitride and MeBr
(4) Borazine and MeMgBr
Show Answer
Answer: (4)
Solution
$\text{H}_3\text{N}_3\text{B}_3\text{Cl}_3 + \text{LiBH}_4 \xrightarrow{\text{THF}} \text{B}_3\text{N}_3\text{H}_6 + \text{LiCl} + \text{BCl}_3$. (B) = Borazine. $\text{H}_3\text{N}_3\text{B}_3\text{Cl}_3 + 3\text{MeMgBr} \to \text{H}_3\text{N}_3\text{B}_3(\text{Me})_3 + 3\text{MgBrCl}$. (C) = MeMgBr.
BETA
