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The ion that has $sp^3d^2$ hybridization for the central atom, is:
(1) $[\text{ICl}_4]^-$
(2) $[\text{ICl}_2]^-$
(3) $[\text{IF}_6]^-$
(4) $[\text{BrF}_2]^-$
$[\text{ICl}_2]^-$: $sp^3d$. $[\text{ICl}_4]^-$: $sp^3d^2$. $[\text{BrF}_2]^-$: $sp^3d$. $[\text{IF}_6]^-$: $sp^3d^3$.
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