JEE PYQ: P Block Elements Question 47
Question 47 - 2019 (09 Apr Shift 1)
The correct order of the oxidation states of nitrogen in NO, $\text{N}_2\text{O}$, $\text{NO}_2$ and $\text{N}_2\text{O}_3$ is:
(1) $\text{NO}_2 < \text{NO} < \text{N}_2\text{O}_3 < \text{N}_2\text{O}$
(2) $\text{NO}_2 < \text{N}_2\text{O}_3 < \text{NO} < \text{N}_2\text{O}$
(3) $\text{N}_2\text{O} < \text{N}_2\text{O}_3 < \text{NO} < \text{NO}_2$
(4) $\text{N}_2\text{O} < \text{NO} < \text{N}_2\text{O}_3 < \text{NO}_2$
Show Answer
Answer: (4)
Solution
$\text{N}_2\text{O}: +1$; NO: $+2$; $\text{N}_2\text{O}_3: +3$; $\text{NO}_2: +4$. So, $\text{N}_2\text{O} < \text{NO} < \text{N}_2\text{O}_3 < \text{NO}_2$.
BETA
