JEE PYQ: P Block Elements Question 60
Question 60 - 2019 (12 Apr Shift 1)
An organic compound ‘A’ is oxidized with $\text{Na}_2\text{O}_2$ followed by boiling with $\text{HNO}_3$. The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate.
Based on above observation, the element present in the given compound is:
(1) Nitrogen
(2) Phosphorus
(3) Fluorine
(4) Sulphur
Show Answer
Answer: (2)
Solution
Phosphorus is detected in the form of yellow ppt of ammonium phosphate molybdate on reaction with ammonium molybdate.
BETA
