JEE PYQ: P Block Elements Question 68
Question 68 - 2019 (10 Jan Shift 1)
The type of hybridisation and number of lone pair(s) of electrons of Xe in $\text{XeOF}_4$, respectively, are:
(1) $sp^3d^2$ and 1
(2) $sp^3d$ and 2
(3) $sp^3d^2$ and 2
(4) $sp^3d$ and 1
Show Answer
Answer: (1)
Solution
$\text{XeOF}_4$: $sp^3d^2$, no. of lone pair $= 1$.