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Chlorine on reaction with hot and concentrated sodium hydroxide gives:
(1) $\text{Cl}^-$ and $\text{ClO}_3^-$
(2) $\text{Cl}^-$ and $\text{ClO}^-$
(3) $\text{ClO}_3^-$ and $\text{ClO}_2^-$
(4) $\text{Cl}^-$ and $\text{ClO}_2^-$
$3\text{Cl}_2 + 6\text{NaOH} \to 5\text{NaCl} + \text{NaClO}_3 + 3\text{H}_2\text{O}$.
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