JEE PYQ: Redox Reactions Question 6
Question 6 - 2021 (24 Feb Shift 1)
$\text{S}{8(s)} + a\text{OH}^-{(aq)} \rightarrow b\text{S}^{2-}_{(aq)} + c\text{S}_2\text{O}_3^{2-}(aq) + d\text{H}2\text{O}{(l)}$
The value of ‘a’ is:
Show Answer
Answer: 12
Solution
S₈ + 12OH⁻ → 4S²⁻ + 2S₂O₃²⁻ + 6H₂O. a = 12.