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(0). (4 g mixture of NaOH, Na₂CO₃ and inert impurities. Titration with N/10 HCl: 17.5 mL (phenolphthalein endpoint), then 1.5 mL (methyl orange endpoint). Weight percentage of Na₂CO₃ is ____.)
n(Na₂CO₃) = 0.15 mmol. W(Na₂CO₃) = 0.15 × 106 × 10⁻³ = 0.0159 g. % = (0.0159/0.4) × 100 ≈ 3%.
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