JEE PYQ: S Block Elements Question 11
Question 11 - 2021 (24 Feb Shift 2)
Match List-I with List-II:
List-I (Salt): (a) LiCl (b) NaCl (c) RbCl (d) CsCl
List-II (Flame colour wavelength): (i) 455.5 nm (ii) 970.8 nm (iii) 780.0 nm (iv) 589.2 nm
(a) (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii) (b) (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i) (c) (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i) (d) (a)-(i), (b)-(iv), (c)-(ii), (d)-(iii)
Show Answer
Answer: (b)
Solution
Flame colours: LiCl gives crimson red (close to red end of visible spectrum, 970.8 nm). NaCl gives golden yellow (589.2 nm). RbCl gives violet (780.0 nm). CsCl gives blue (455.5 nm). So LiCl→(ii), NaCl→(iv), RbCl→(iii), CsCl→(i).
BETA
