JEE PYQ: S Block Elements Question 6
Question 6 - 2021 (18 Mar Shift 1)
Match List-I with List-II:
List-I: (a) $\text{Ca(OCl)}_2$ (b) $\text{CaSO}_4 \cdot \frac{1}{2}\text{H}_2\text{O}$ (c) CaO (d) $\text{CaCO}_3$
List-II: (i) Antacid (ii) Cement (iii) Bleach (iv) Plaster of paris
(a) a-i, b-iv, c-iii, d-ii (b) a-iii, b-ii, c-iv, d-i (c) a-iii, b-iv, c-ii, d-i (d) a-iii, b-ii, c-i, d-iv
Show Answer
Answer: (c)
Solution
$\text{Ca(OCl)}_2$ is Bleach (iii). $\text{CaSO}_4 \cdot \frac{1}{2}\text{H}_2\text{O}$ is Plaster of Paris (iv). $\text{CaCO}_3$ is used as an antacid (i). CaO is a major component of cement (ii).
BETA
