JEE PYQ: Solid State Question 17
Question 17 - 2019 (12 Apr Shift 2)
The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are, respectively:
(1) 8 : 1 : 6
(2) 1 : 2 : 4
(3) 4 : 2 : 1
(4) 4 : 2 : 3
Show Answer
Answer: (2)
Solution
Simple cubic: $\dfrac{1}{8} \times 8 = 1$. BCC: $\dfrac{1}{8} \times 8 + 1 \times 1 = 2$. FCC: $\dfrac{1}{8} \times 8 + \dfrac{1}{2} \times 6 = 4$. Ratio = 1 : 2 : 4.
BETA
