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JEE PYQ: Solid State Question 19

Question 19 - 2019 (09 Jan Shift 2)

At 100$^\circ$C, copper (Cu) has FCC unit cell structure with cell edge length of $x$ $\text{\AA}$. What is the approximate density of Cu (in g cm$^{-3}$) at this temperature?

[Atomic Mass of Cu $= 63.55$ u]

(1) $\dfrac{205}{x^3}$

(2) $\dfrac{105}{x^3}$

(3) $\dfrac{211}{x^3}$

(4) $\dfrac{422}{x^3}$

Show Answer

Answer: (4)

Solution

We know that density $= \dfrac{Z \times M}{N_A \times a^3}$. Given that $Z = 4$ (fcc), $M = 63.5$ g, $N_A = 6 \times 10^{23}$, $a = x \times 10^{-8}$ cm. $d = \dfrac{4 \times 63.5}{6 \times 10^{23} \times x^3 \times 10^{-24}} = \dfrac{422}{x^3}$ g cm$^{-3}$.


Learning Progress: Step 19 of 23 in this series