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JEE PYQ: Solid State Question 22

Question 22 - 2019 (11 Jan Shift 1)

A solid having density of $9 \times 10^3$ kg m$^{-3}$ forms face centred cubic crystals of edge length $200\sqrt{2}$ pm. What is the molar mass of the solid?

[Avogadro constant $\approx 6 \times 10^{23}$ mol$^{-1}$, $\pi \approx 3$]

(1) 0.0432 kg mol$^{-1}$

(2) 0.0216 kg mol$^{-1}$

(3) 0.0305 kg mol$^{-1}$

(4) 0.4320 kg mol$^{-1}$

Show Answer

Answer: (3)

Solution

Density $= \dfrac{Z \times M}{N_A \times a^3}$. $9 \times 10^3 = \dfrac{4 \times M}{\left(200\sqrt{2} \times 10^{-12}\right)^3 \times 6 \times 10^{23}}$. $M = 305.4 \times 10^{-4} = 0.0305$ kg/mol.


Learning Progress: Step 22 of 23 in this series