JEE PYQ: Solid State Question 6
Question 6 - 2021 (25 Feb Shift 2)
The unit cell of copper corresponds to a face centered cube of edge length $3.596 \text{ \AA}$ with one copper atom at each lattice point. The calculated density of copper in $\text{kg/m}^3$ is ___ [Molar mass of Cu: 63.54 g; Avogadro number $= 6.022 \times 10^{23}$]
Show Answer
Answer: 9077
Solution
$a = 3.596 \text{ \AA}$, $d = \dfrac{Z \times M}{N_A \times a^3} = \dfrac{4 \times 63.54 \times 10^{-3}}{6.022 \times 10^{23} \times (3.596 \times 10^{-10})^3}$. $d = 0.9076 \times 10^4 = 9076.2 \text{ kg/m}^3 \approx 9077$.
BETA
