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JEE PYQ: Solutions And Colligative Properties Question 15

Question 15 - 2020 (03 Sep Shift 1)

Henry’s constant (in kbar) for four gases $\alpha$, $\beta$, $\gamma$ and $\delta$ in water at 298 K is given below:

$\alpha$ $\beta$ $\gamma$ $\delta$
$K_H$ 50 2 $2 \times 10^{-5}$ 0.5

(density of water $= 10^3$ kg m$^{-3}$ at 298 K)

(1). ($\alpha$ has the highest solubility in water at a given pressure)

(2). (solubility of $\gamma$ at 308 K is lower than at 298 K)

(3). (The pressure of a 55.5 molal solution of $\gamma$ is 1 bar)

(4). (The pressure of a 55.5 molal solution of $\delta$ is 250 bar)

Show Answer

Answer: (4)

Solution

For $\delta$: $P = 0.5 \times \frac{55.5}{55.5 + 1000/18} = 0.25$ kbar $= 250$ bar.


Learning Progress: Step 15 of 46 in this series