JEE PYQ: Solutions And Colligative Properties Question 16
Question 16 - 2020 (03 Sep Shift 2)
If 250 cm$^3$ of an aqueous solution containing 0.73 g of a protein A is isotonic with one litre of another aqueous solution containing 1.65 g of a protein B, at 298 K, the ratio of the molecular masses of A and B is ____ $\times 10^{-2}$.
Show Answer
Answer: 177
Solution
$\frac{M_A}{M_B} = \frac{0.73 \times 4}{1.65} = 1.77 = 177 \times 10^{-2}$.
BETA
