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What would be the molality of 20% (mass/mass) aqueous solution of KI? (molar mass of KI $= 166$ g mol$^{-1}$)
(1). (1.08)
(2). (1.35)
(3). (1.48)
(4). (1.51)
20 g KI in 80 g water. Molality $= \frac{0.121 \times 1000}{80} = 1.51$ m.
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