JEE PYQ: States Of Matter Question 20
Question 20 - 2019 (09 Jan Shift 1)
(0). (5 moles of gas A and $x$ moles of gas B exert a pressure of 200 Pa in a container of volume 10 m$^3$ at 1000 K. Given $R$ is the gas constant in $\text{JK}^{-1}\text{mol}^{-1}$, $x$ is:)
(1) $\frac{2R}{4+R}$ (2) $\frac{2R}{4-R}$ (3) $\frac{4+R}{2R}$ (4) $\frac{4-R}{2R}$
Show Answer
Answer: (4) $\frac{4-R}{2R}$
Solution
$PV = nRT$; $200 \times 10 = (0.5 + x) \times R \times 1000$; $x = \frac{4-R}{2R}$.
BETA
