JEE PYQ: States Of Matter Question 22
Question 22 - 2019 (12 Jan Shift 1)
An open vessel at $27^\circ\text{C}$ is heated until two fifth of the air has escaped. The temperature at which the vessel has been heated is:
(1) $500^\circ\text{C}$ (2) 500 K (3) $750^\circ\text{C}$ (4) 750 K
Show Answer
Answer: (2) 500 K
Solution
$n_2 = n_1 - \frac{2n_1}{5} = \frac{3n_1}{5}$. At constant P, V: $n_1T_1 = n_2T_2$; $T_2 = \frac{5}{3} \times 300 = 500$ K.
BETA
