JEE PYQ: States Of Matter Question 24
Question 24 - 2019 (12 Jan Shift 2)
The volume of gas A is twice than that of gas B. The compressibility factor of gas A thrice than that of gas B at same temperature. The pressures of the gases for equal number of moles are:
(1) $3P_A = 2P_B$ (2) $2P_A = 3P_B$ (3) $P_A = 3P_B$ (4) $P_A = 2P_B$
Show Answer
Answer: (2) $2P_A = 3P_B$
Solution
$Z = \frac{PV}{nRT}$; $\frac{Z_A}{Z_B} = \frac{P_A V_A}{P_B V_B}$; $3 = \frac{P_A \times 2}{P_B}$; $2P_A = 3P_B$.
BETA
