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(0). (12 g of oxygen is adsorbed on 1.2 g of platinum metal. The volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 300 K is ____ [$R = 0.0821$ L atm $\text{K}^{-1} \text{mol}^{-1}$])
Moles of $\text{O}_2 = \frac{0.12}{32} = 0.00375$. Volume $= 0.00375 \times 0.0821 \times 300 = 2.4$ L. Per gram of Pt $= \frac{2.4}{1.2} = 2$.
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