JEE PYQ: Thermodynamics Question 24
Question 24 - 2019 (09 Apr Shift 2)
During compression of a spring the work done is 10 kJ and 2 kJ escaped to the surroundings as heat. The change in internal energy, $\Delta U$ (in kJ) is:
(1) $-12$
(2) $-8$
(3) 8
(4) 12
Show Answer
Answer: (3)
Solution
$w = 10$ kJ. $q = -2$ kJ. $\Delta U = q + w = -2 + 10 = 8$ kJ.