JEE PYQ: Thermodynamics Question 29
Question 29 - 2019 (12 Apr Shift 2)
The INCORRECT match in the following is:
(1) $\Delta G^0 < 0, K > 1$
(2) $\Delta G^0 = 0, K = 1$
(3) $\Delta G^0 > 0, K < 1$
(4) $\Delta G^0 < 0, K < 1$
Show Answer
Answer: (4)
Solution
$\Delta G^\circ = -RT\ln K$. If $K > 1$ then $\Delta G^\circ < 0$. If $K < 1$ then $\Delta G^\circ > 0$. If $K = 1$ then $\Delta G^\circ = 0$. So option (4) is the incorrect match.