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JEE PYQ: Thermodynamics Question 29

Question 29 - 2019 (12 Apr Shift 2)

The INCORRECT match in the following is:

(1) $\Delta G^0 < 0, K > 1$

(2) $\Delta G^0 = 0, K = 1$

(3) $\Delta G^0 > 0, K < 1$

(4) $\Delta G^0 < 0, K < 1$

Show Answer

Answer: (4)

Solution

$\Delta G^\circ = -RT\ln K$. If $K > 1$ then $\Delta G^\circ < 0$. If $K < 1$ then $\Delta G^\circ > 0$. If $K = 1$ then $\Delta G^\circ = 0$. So option (4) is the incorrect match.


Learning Progress: Step 29 of 40 in this series