JEE PYQ: Thermodynamics Question 9
Question 9 - 2020 (04 Sep Shift 2)
Five moles of an ideal gas at 1 bar and 298 K is expanded into vacuum to double the volume. The work done is:
(1) $C_V(T_2 - T_1)$
(2) $-RT(V_2 - V_1)$
(3) $-RT\ln V_2/V_1$
(4) zero
Show Answer
Answer: (4)
Solution
In expansion against vacuum, $P_{ext} = 0$. $W = -P_{ext}\Delta V = 0$. $W = 0$.