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JEE PYQ: Thermodynamics Question 9

Question 9 - 2020 (04 Sep Shift 2)

Five moles of an ideal gas at 1 bar and 298 K is expanded into vacuum to double the volume. The work done is:

(1) $C_V(T_2 - T_1)$

(2) $-RT(V_2 - V_1)$

(3) $-RT\ln V_2/V_1$

(4) zero

Show Answer

Answer: (4)

Solution

In expansion against vacuum, $P_{ext} = 0$. $W = -P_{ext}\Delta V = 0$. $W = 0$.


Learning Progress: Step 9 of 40 in this series