JEE PYQ: Application Of Derivatives Question 27
Question 27 - 2020 (02 Sep Shift 1)
Let $P(h, k)$ be a point on the curve $y = x^2 + 7x + 2$, nearest to the line, $y = 3x - 3$. Then the equation of the normal to the curve at $P$ is:
(1) $x + 3y + 26 = 0$
(2) $x + 3y - 62 = 0$
(3) $x - 3y - 11 = 0$
(4) $x - 3y + 22 = 0$
Show Answer
Answer: (1)
Solution
$\frac{dy}{dx} = 2h + 7 = 3 \Rightarrow h = -2$. $k = 4 - 14 + 2 = -8$. Slope of normal $= -\frac{1}{3}$. Equation: $x + 3y + 26 = 0$.
BETA
