JEE PYQ: Application Of Derivatives Question 38
Question 38 - 2020 (05 Sep Shift 2)
Which of the following points lies on the tangent to the curve $x^4 e^y + 2\sqrt{y+1} = 3$ at the point $(1, 0)$?
(1) $(2, 2)$
(2) $(2, 6)$
(3) $(-2, 6)$
(4) $(-2, 4)$
Show Answer
Answer: (3)
Solution
Differentiating: $(4x^3 e^y + x^4 e^y y’) + \frac{y’}{\sqrt{y+1}} = 0$. At $(1,0)$: $4 + y’ + y’ = 0 \Rightarrow y’ = -2$. Tangent: $y = -2(x-1) \Rightarrow 2x + y = 2$. $(-2, 6)$ satisfies this.
BETA
