JEE PYQ: Application Of Derivatives Question 70
Question 70 - 2019 (09 Jan Shift 1)
If $\theta$ denotes the acute angle between the curves $y = 10 - x^2$ and $y = 2 + x^2$ at a point of their intersection, then $|\tan\theta|$ is equal to:
(1) $\frac{4}{9}$
(2) $\frac{8}{15}$
(3) $\frac{7}{17}$
(4) $\frac{8}{17}$
Show Answer
Answer: (2)
Solution
At intersection: $10 - x^2 = 2 + x^2 \Rightarrow x = \pm 2$. At $(2,6)$: slopes are $-4$ and $4$. $\tan\theta = \left|\frac{-4-4}{1+(-4)(4)}\right| = \frac{8}{15}$.
BETA
